https://tw.18dao.net/index.php?action=history&feed=atom&title=Arius_Jewellery_%E9%80%81_%E7%B2%BE%E9%81%B8%E8%81%96%E8%AA%95%E7%A6%AE%E7%89%A9
Arius Jewellery 送 精選聖誕禮物 - 修訂歷史
2026-07-27T01:40:40Z
本 Wiki 上此頁面的修訂歷史
MediaWiki 1.27.0
https://tw.18dao.net/index.php?title=Arius_Jewellery_%E9%80%81_%E7%B2%BE%E9%81%B8%E8%81%96%E8%AA%95%E7%A6%AE%E7%89%A9&diff=874501&oldid=prev
Li Xuechao：已建立頁面，內容為 "{{香港優惠券/內容頂部}} <div class='fieldset'> == 香港優惠券 == <div class='left_column'> {{Bottom}} </div> <div class='right_column'> Arius Jewellery..."
2018-12-11T08:02:56Z
<p>已建立頁面，內容為 "{{香港優惠券/內容頂部}} <div class='fieldset'> == 香港優惠券 == <div class='left_column'> {{Bottom}} </div> <div class='right_column'> Arius Jewellery..."</p>
<p><b>新頁面</b></p><div>{{香港優惠券/內容頂部}}<br />
<div class='fieldset'><br />
== 香港優惠券 ==<br />
<div class='left_column'><br />
{{Bottom}}<br />
</div><br />
<div class='right_column'><br />
<br />
Arius Jewellery<br />
<br />
店主呢輪聽到有朋友????♂️講參加左上次個有奬問答遊戲但又揀唔中????, 問可唔可以襯聖誕節再攪多次喎????…收到收到小編收到了????, 真係估唔到會個活動受歡迎????, 咁啦, 不如今次又玩個遊戲就, 答啱又完成以下步驟就有機會會被隨機揀中(5名), 提早收到我地為你準備圖中或精選既聖誕禮物????乙份????<br />
<br />
1. 記得Like 我地專頁:<br />
[https://www.facebook.com/Arius-Jewellery-570971429704442/ 點擊]<br />
<br />
2. Like & Share此Post<br />
<br />
3. 留言: Arius Jewellery<br />
<br />
4.Tag 5 位朋友<br />
<br />
截止日期: 24 Dec 2018 晚上10時, 被揀中既朋友(名額5名,會以順豐到付)會有專人inbox 你領取禮品, 逾期將會作廢!<br />
<br />
<br />
<br />
<br />
[https://www.facebook.com/AriusJewellery/photos/a.580535715414680/1493806197420956/?type=3&__xts__%5B0%5D=68.ARAfB3W-EAQIupPs1yDe4qhL9E75oqov7NpJ6VQZ8I-cKcN6ev3a7djCTv5p8eXbyEuBXTn2mclHYJlRqo8DVEBtWh98F0xG17ijMmdBBY5mrcfdK4W-hA3CUBPCdZeCXrcuaXJS64GyoWaNp2K9xNRre91SBGzCe56f3dy87mU0K0b7lZe4jmWbY_c1Ws1zL4OhGytUUhryfW__ExOVV3k8IcUlbTYMpxzUIWHRks4P5rtq4MwZo7oqA9HmwgiQAVefJt0nOLlHibhwhWoVsa720uqppkAFV6P7tY8hi262JxpIwlDc2ruNld9elOg7JqpJFlYGEK00nLDkYEfZfvS4kQ&__tn__=H-R 詳情請點擊]<br />
<br />
[[檔案:Arius Jewellery 送 精選聖誕禮物.jpg|336px|left]]<br />
<br />
</div><br />
</div><br />
<div class='clear-both'><br />
</div><br />
[[Category:香港]]<br />
<br />
{{香港優惠券/內容底部}}</div>
Li Xuechao